If the angular momentum of an electron is `vec(J)` then the magnitude of the magnetic moment will be

Options

A. eJ2m
B. `(2m)/(eJ)`
C. `(eJ)/(2m)`
D. `(eJ)/(m)`

Answer

C

Explanation

The magnetic moment of an electron revolving in a circular orbit of radius r is `M=1.2 evr`
and its angular momentum
`J=I omega =mr^(2)xx(v)/(r )="mvr"`
`therefore (M)/(J)=1/2("evr")/("mvr")=1/2("e ")/("m") therefore M=("eJ")/(2m)`