The friction coefficient between the blocks is `0.5`. Find the acceleration of each block if `F` is equal to (a) `5 N` and (b) `20 N`.

Explanation

(a) `f_(max) = mu N_(0) = 0.5 xx 20 = 10 N`
`10 gt 5` , the upper block will not move w.r.t. the lower block. In fact both the blocks will move together as a single block.
`5 = ( 2 + 3)a rArr a = 1 m//s^(2)`
(b) `F = 20 N` , the blocks will move with different accelerations
`20 - 10 = 2 a_(1) rArr a_(1) = 5 m//s^(2)`
`10 = 3 a_(2) rArr a_(2) = (10)/(3) m//s^(2)`