A car is moving along a stight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyres and the road is mu, the shortest distance in which the car can be stopped is.

Options

A. `(v_(0)^(2))/( 2mu g)`
B. `(v_(0))/( mu g)`
C. `((v_(0))/(mu g))^(2)`
D. `(v_(0))/(mu)`

Answer

A

Explanation

`0 = v_(0)^(2) - 2mu gs rArr s = (v_(0)^(2))/( 2mu g)`