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A block is at rest on an inclined plane ...

A block is at rest on an inclined plane making an angle `alpha` with the horizontal . As the angle `alpha` of the incline is increased the block starts slipping when the angle of inclination becomes `theta`. The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle `theta` to the horizontal. Then the coefficient of friction is equal to

A

`sin theta`

B

`cos theta`

C

`tan theta`

D

Independent of `theta`

Text Solution

Verified by Experts

The correct Answer is:
C
The block will move downwards
`mg sin theta = mu g cos theta rArr mu = tan theta`
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Knowledge Check

  • A block is at rest on an inclined plane making an angle alpha with the horizontal. As the angle of the incline is increased the block start slipping when the angle of inclination becomes theta then coefficient of friction is equal to

    A
    `sintheta`
    B
    `costheta`
    C
    `tantheta`
    D
    Independent of `theta`

  • A block of mass m is placed at rest on an inclination theta to the horizontal.If the coefficient of friction between the block and the plane is mu , then the total force the inclined plane exerts on the block is

    A
    `mg`
    B
    `mu mg cos theta`
    C
    ` mg sin theta`
    D
    `mu mg tan theta`

  • A body is sliding down an inclined plane forming an angle 30^(@) with the horizontal. If the coefficient of friction is 0.3 then acceleration of the body is

    A
    `1.25 ms^(-2)`
    B
    `2.35 ms^(-2)`
    C
    `3.4 ms^(-2)`
    D
    `4.9 ms^(-2)`

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