Consider a horizontally oriented syringe containing water located of a height of `1.25 m` above the ground. The diameter of plunger is `8 mm` and the diameter if the nozzle is `2 mm`. The plunger is pushed with a constant speed of `0.25 m//s`. Find the horizontal range of water stream on the ground. Take `g = 10 m//s^2`.
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Explanation

By continuity equation between `C` and `A`
`AV = av`
`(pi)/(4) D^2 V = (pi)/(4) d^2 v`
`v = ((D)/(d))^2 V = ((8)/(2))^2 xx 0.25 = 4 m//s`
Projectile motion between `A` and `B`
`h = (1)/(2) g t^2`
`t = sqrt((2h)/(g)) = sqrt((2 xx 1.25)/(10)) = 0.5 s`
`R = vt = 4 xx 0.5`
=`2 m`.

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