In a hydraulic press the small cylinder has a diameter of `'d_1' cm`, while the large piston has a diameter of `'d_2' cm`. If a force `'F_1'` is applied to a small piston, the force on the large piston `'F_2'` is given by.

Options

A. `F_2 = (d_2^2)/(d_1^2) F_1`
B. `F_2 = (d_1^2)/(d_2^2) F_1`
C. `F_2 = (d_1^2)/(d_2^2) (1)/(F_1)`
D. `F_2 = (d_1^2)/(d_1^2) (1)/(F_1)`

Answer

A

Explanation

`(((F_1)/(pi d_1^2))/(4)) ((pi d_2^2)/(4)) = F_2`
`F_2 = (F_1 d_2^2)/(d_1^2)`.
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