A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross section `A_(1)` and `A_(2)` are `v_(1)` and `v_(2)` respectively. The difference in the levels of the liquid in the two vertical tubes is `h`. Then

Options

A. (i),(ii)
B. (i),(iii)
C. (i),(iii),(iv)
D. (iii),(iv)

Answer

C

Explanation

`p_1 + (1)/(2) rho v_1^2 = p_2 + (1)/(2) rho v_2^2`
`(p_1 - p_2) = (1)/(2) rho(v_2^2 - v_1^2)`
`rho gh = (1)/(2) rho(v_2^2 - v_1^2)`
`v_2^2 - v_1^2 = 2 gh`.