In the figure, an ideal flows through the tube, which is of uniform cross-section. The liquid has velocities `v_A` and `v_B` and pressures `p_A` and `p_B` at points `A` and `B` respectively.
(i) `v_A = v_B`
(ii) `v_B gt v_A` ltbr gt (iii) `p_A = p_B`
(iv) `p_B gt p_A`.
.

Options

A. (i),(iii)
B. (i),(iv)
C. (ii),(iii)
D. (ii),(iv)

Answer

B

Explanation

Since cross-section is uniform, `v_A = v_B`
`p_A + rho gh = p_B`.