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In the previous question will be its tem...

In the previous question will be its temperature 5 min after reaching `40^(@)C`?

A

`35^(@)C`

B

`(100)/(3)^(@)C`

C

`32^(@)C`

D

`30^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B

(2) `(40 - theta)/(5) = - k ((40 + theta)/(2) - 20)`
`(40 - theta)/(5) = (2)/(25) ((theta)/(2))`
`200 - 5 theta = theta implies theta = (100)/(3).^(@)C`
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