A black body is at a temperature of `2800K` The energy of radiation emitted by this object with wavelength between `499nm` and 500 nm is `U_(1)` between 999nm and 1000nm is `U_(2)` and between 1499 nm and 1500 nm is `U_(3)` The Wien's constant `b =2.80 xx 10^(6)` nm `K` Then .

Options

A. `U_(1) = 0`
B. `U_(3) = 0`
C. `U_(1) gt U_(2)`
D. `U_(2) gt U_(1)`

Answer

D

Explanation

(4) `lambda_(m) T = b`
`lambda_(m) xx 2880 = 2.88 xx 10^(6)`
`lambda_(m) = 1000 mm`
`lambda (nm)`
`U_(2) gt U_(1)`