The following figure shows the displacement versus time graph for two particles A and B executing simple harmonic motions. The ratio of their maximum velocities is

Explanation

For `A`, time period `T_(A) = 16s`, amplitude `A_(A) = 1cm`
For `B`, time period `T_(B) = 24 s`, amplitude `A_(B) = 5cm`
Ratio of maximum velocities
`(V_(A))/(V_(B)) = (A_(A^(•)A))/(A_(B^(•)B)) =(A_(A)T_(B))/(A_(B)T_(A)) =(10xx24)/(5xx16)=(3)/(1)`