A body executes `SHM`, such that its velocity at the mean position is `1ms^(-1)` and acceleration at exterme position is `1.57 ms^(-2)`. Calculate the amplitude and the time period of oscillation.

Explanation

To solve the problem step by step, we will use the formulas related to Simple Harmonic Motion (SHM) and the given data.

### Step 1: Identify the given values
- Velocity at the mean position, \( V_{max} = 1 \, \text{m/s} \)
- Acceleration at the extreme position, \( A_{max} = 1.57 \, \text{m/s}^2 \)

### Step 2: Use the formulas for maximum velocity and maximum acceleration in SHM
The maximum velocity \( V_{max} \) in SHM is given by:
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