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A point mass oscillates along the x-axis...

A point mass oscillates along the x-axis according to the law `x=x_(0) cos(moegat-pi//4). If the acceleration of the particle is written as `a=A cos(omegat+delta), the .

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Velocity `v = (dx)/(dt) =- x_(0) omega sin (omegat -(pi)/(4))`
Acceleration `a = (dv)/(dt) =- x_(0) omega^(2) cos (omegat -(pi)/(4))`
`a = x_(0) omega^(2) cos(omegat+(3pi)/(4)) ….(1)`
Given that `a = A cos (omegat +delta) ….(2)`
from (1) & (2), `A = x_(0) omega^(2), delta = (3pi)/(4)`
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NARAYNA-OSCILLATIONS-EXERCISE - IV
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