A linear harmonic oscillator of force constant `2 xx 10^6 N//m` and amplitude (0.01 m) has a total mechanical energy of (160 J). Its.

Explanation

`K.E_(max) = (1)/(2)KA^(2) = (1)/(2)xx2xx10^(6) xx (0.01)^(2) = 100J`
Since total energy is `160J`. Maximum `P.E.` is `160J`. From this is understood that at the mean position potential energy of the simple harmonic osciallator is minimum which need not be zero.
`PE_(min) = TE - KE_(max) =160 - 100 = 60 J`
`KE_(min) = 0`