A particle of mass `1 kg` is executing `SHM` with an amplitude of `1m` and time pariod. `pis`. Calculate kinetic enegry of the particle at the moment when the displacement is `0.8 m`.

Explanation

`omega = (2pi)/(T) = (2pi)/(pi) = 2s`
We have, `v = omega sqrt(A^(2) - x^(2))`
`v = 2 sqrt((1)^(2)-(0.8)^(2)) = 2xx0.6 = 1.2 m//s`
Kinetic energy `=(1)/(2) mv^(2) = (1)/(2) xx1 xx (1.2)^(2) = 0.72 J`