The potential energy of a particle of mass `1kg` in motion along the x- axis is given by: `U = 4(1 - cos 2x)`, where `x` in meters. The period of small oscillation (in sec) is

Explanation

`F =- (dU)/(dx) = -(d)/(dx) [4-4cos 2x]`
`=+4 (2) (-sin 2x) =- 8 sin 2x`
here 'x' is small `:. Sin 2x = 2x`
So `F =- 16 x rArr m omega^(2) = 16 rArr 4 omega^(2) = 16`
`rArr omega = 2 rArr T = 2pi//omega = pi` seconds