The displacement of `SHO` is, `y = 6 sin(pit +pi//3)` find (1) Instants at which `PE` is minimum (or) `KE` is maximum. (2) Instants at which `PE` is maximum (or) `KE` is minimum.

Explanation

`PE` is minimum (or) `KE` is maximum when `SHO` is at mean position i.e., `y =0`
`y = 0 = 6 sin (pit +pi//3)`
`rArr pi(t+(1)/(3)) =npi` here `n =1,2,3….`
`t = n-(1)/(3)`
`PE` is maximum (or) `KE` is minimum at `y = +-A`
When `y = +- 6` i.e `sin (pit + pi//3) = +1`
`(pit+(pi)/(3)) =(2n+1) (pi)/(2)` here `n = 0,1,2,3...`
`t = (1)/(3) =(2n+1)/(2)(s), t = n+(1)/(2)-(1)/(3) (s)`