A mass `m = 8 kg` is attached to a spring passing over a pulled whose other end is fixed to ground and held in position so that the spring remains unstretched. The spring constant is `200 N//m`. The mass `m` is then released and begins to undergo small oscillations. Find maximum velocity of mass

Explanation

Mean position will be at `Kx = mg`
or `x = (mg)/(K) = (8 xx 10)/(200) =(2)/(5) = 0.4 m` This is also the amplitude of oscillation `A = 0.4m`
`V_(max) = A• = A sqrt((K)/(m)) = (0.4) sqrt((200)/(8)) = 2m//s`