A uniform rod of mass 'm' and length 'l' is hinged at one end 'A'. It can rotate freely about a horizontal axis passing through 'A'. If it is given a sloght angular displacement and left to itself then it oscillate. Find the time period of small oscillations.

Explanation

here `I = (ml^(2))/(3), d = (l)/(2)` (distance from `COM` to point of suspension)
`T = 2pi sqrt((I)/(mgd)) = 2pi sqrt((ml^(2))/(3mg.(l)/(2))) = 2pi sqrt((2l)/(3g))`
Note: Equivalent length of simple pendulum `l_(eq) = (2l)/(3)`