Two simple harmonic motion `y_(2) A sin omegat` and `y_(2)=A cos omegat` are superimposed on a particle of mass `m`. The total mechanical energy of the particle is:

Explanation

Phase difference between the two `SHM` is `90^(@)` Therefore, resultant amplitude is

`A_(R) = sqrt(2)A, TE = (1)/(2) m•^(2) = A_(R)^(2)`
`= (1)/(2) m•^(2) (sqrt(2)A)^(2) = m•^(2) A^(2)`