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A particle is executing a simple harmoni...

A particle is executing a simple harmonic motion its maximum acceleration is a and maximum velocity is `beta` .Then its time of vibration will be

A

`beta^(2) alpha`

B

`alpha^(2)beta`

C

`(beta^(2))/(alpha)`

D

`(alpha^(2))/(beta)`

Text Solution

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The correct Answer is:
C
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