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In SHM at the equilibrium position (i)...

In `SHM` at the equilibrium position
(i) displacement is minimum
(ii) acceleration is zero
(iii) velocity is maximum
(iv) potential energy is maximum

A

all are true

B

ii,iii,iv are true

C

ii,iii true

D

i,ii,iv true

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • In S.H.M. maximum acceleration is a

    A
    Amplitude
    B
    Equilibrium
    C
    Acceleration is constant
    D
    None of these

  • Acceleration -time graph of a particel executing SHM is as shown in fig. Then (i) displacement of particle at 1 is -ve (ii) velocity of particel at 2 is +ve (iii) potential enegry of particel at 3 is maximum (iv) speed of particel at 4 is decreasing.

    A
    only i, ii, are correct
    B
    only i,iii,iv are correct
    C
    only ii,iii,iv are correct
    D
    all are correct

  • In a simple harmonic motion (i) the maximum potential energy equal the maximum kinetic energy (ii) the minimum potential energy equals the minimum kinetic energy (iii) the minimum potential energy equals the maximum kinetic energy (iv) the maximum potential energy equals the minimum kinetic energy

    A
    (i),(ii)
    B
    (i),(iii)
    C
    (ii),(iii)
    D
    (i), (iv)

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