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The period of a particle in SHM is 8s. A...

The period of a particle in SHM is `8s`. At `t=0` it is at the mean position. The ratio of the distances travled by it in the first and the second second is

A

`(1)/(2)`

B

`(1)/(sqrt(2))`

C

`sqrt(2)`

D

`sqrt(2)+1`

Text Solution

Verified by Experts

The correct Answer is:
D
`y_(1) =Asin ((2pi)/(T)xxt_(1)), y_(2) = A sin ((2pi)/(T)xx(t_(1)+t_(2)))` Distance travelled in second, `y_(2)^(1) = y_(2) - y_(1)`
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