Two simple harmonic are represented by the equation `y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit`.
The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.

Options

A. `(-pi)/(3)`
B. `(pi)/(6)`
C. `(-pi)/(6)`
D. `(pi)/(3)`

Answer

C

Explanation

`v_(1) = (dy_(1))/(dt) = A_(1)omega_(1)cos (omega_(1)t +phi_(1))`
`v_(2) =(dy_(2))/(dt) = A_(2)omega_(2)sin (omega_(2)t+phi_(2)) Deltaphi = phi_(1) - phi_(2)`