A particle is moving in a circel of radius `R = 1m` with constant speed `v =4 m//s`. The ratio of the displacement to acceleration of the foot of the perpendicular drawn from the particle onto the diameter of the circel is

Options

A. `(1)/(16)s^(2)`
B. `(1)/(2)s^(2)`
C. `2s^(2)`
D. `16s^(2)`

Answer

A

Explanation

`omega =(v)/(R ) , (x)/(a) = (1)/(omega^(2))`