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A particle under the action of a force h...

A particle under the action of a force has a period of `3s` and under the action of another force it has a period `4sec` in `SHM`. What will be its period under the combined action of both forces in the same direction?

A

`7s`

B

`5s`

C

`2.4s`

D

`0.4s`

Text Solution

Verified by Experts

The correct Answer is:
C
`T = (T_(1)T_(2))/(sqrt(T_(1)^(2)+T_(2)^(2)))`
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