For a particle executing `SHM`, the kinetic energy `(K)` is given by `K = K_(0)cos^(2) omegat`. The equation for its displacement is

Options

A. `((K_(0))/(m omega^(2)))^((1)/(2)) sin omegat`
B. `((2K_(0))/(m omega^(2)))^((1)/(2)) sin omegat`
C. `((2omega^(2))/(m K_(0)))^((1)/(2)) sin omegat`
D. `((2K_(0))/(m omega^(2)))^((1)/(2)) sin omegat`

Answer

B

Explanation

`KE_(max) = K_(0) = (1)/(2)m omega^(2) a^(2), y = a sin omegat`