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A mass M is suspended from a spring of n...

`A` mass `M` is suspended from a spring of negligible mass. The spring is pulled a little then released, so that the mass executes simple harmonic motion of time period `T`. If the mass is increased by `m`, the time period becomes `(5T)/(3)`. Find the ratio of `m//M`.

A

`(9)/(16)`

B

`(25)/(16)`

C

`(16)/(9)`

D

`(4)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(T^(1))/(T) = sqrt((M+m)/(M))`
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