The matallic bob of a simple pendulum has the relative density `rho`. The time period of this pendulum is `T` it the metallic bob is immersed in water the new time period is given by

Options

A. `T = ((rho-1)/(rho))`
B. `T((rho)/(rho-1))`
C. `Tsqrt((rho-1)/(rho))`
D. `T sqrt((rho)/(rho-1))`

Answer

D

Explanation

`T = 2pi sqrt((l)/(g)), T = 2pi sqrt((l)/(g_(eff))), g_(eff) = g (1-(rho_(liq))/(rho_(bob)))`