A pendulum suspended from the roof of an elevator at rest has a time period `T_(1)`, when the elevator moves up with an acceleration `a` its time period becomes `T_(2)`, when the elevator moves down with an acceleration `a`, its time period becomes `T_(3)`, then

Options

A. `T_(1) = sqrt((T_(3)T_(2)))`
B. `T_(3) = sqrt((T_(1)^(2)+T_(2)^(2)))`
C. `T_(1) = (sqrt(2)T_(2)T_(3))/(sqrt(T_(2)^(2)+T_(3)^(2)))`
D. `T_(1) = (T_(2)^(2))/(T_(3))`

Answer

C

Explanation

`T alpha(1)/(sqrt(g))`