Time period of a simple pendulum inside a lift that is accelerating up at `2ms^(-2)` is `T_(1)`. If left is retarding down at `6ms^(-2)` then time period of same pendulum is `T_(1)`. Then `T_(1)//T_(2)` is

Options

A. `sqrt((1)/(3))`
B. `sqrt((4)/(3))`
C. `sqrt((3)/(4))`
D. `sqrt(3)`

Answer

B

Explanation

`(T_(1))/(T_(2)) = sqrt((g+a_(2))/(g+a_(1)))`