A pendulum has a period `T` for small osillations. An obstacle is placed directly beneath the pivot, so that only the lowest one - quarter of the string can follow the pendulum bob when it swings to the left of its resting position. The pendulum is released from rest at a certain point. How long will it take to return to that point again ? In answering this question, you may assume that the angle between the moving string and the vertical stays small throughout the motion.

Options

A. `T//2`
B. `3T//4`
C. `T//4`
D. `T`

Answer

B

Explanation

`t =(T)/(2)+(T^(1))/(2), T^(1) = 2pi sqrt((l)/(4g)) = (T)/(2)`