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Statement-I : Two cubical blocks of same...

Statement-I : Two cubical blocks of same material and of sides `a` and `2a`, respectively are attached rigidly and symmetrically to each other as shown. The system of two blocks of floating in water in such a way that upper surface to bigger block is just submerged in the water. If the system of blocks is displaced slightly in vertical directions, then the amplitude of oscillation on either side of equilibrium position would be different.

Statement-II: The force constant on two sides of equlibrium position in the above-described situation is different.

A

Statement-I is true, Statement-Ii is true, Statement-II is a correct explanation for Statement-I.

B

Statement-I is true, Statement-II is true, Statement-II is NOT a correct explanantion for Statement-I.

C

Statement-I is true, Statement-II is false

D

Statement-I is false, Statement-II is true

Text Solution

Verified by Experts

The correct Answer is:
A
Let `rho_(0) =` density of meterial of cube `rho =` density of liquid `:.` at equilibrium position:
`9 rho_(0) = 8 rho …(1)`. If the block is displaced down by `x` above mean position.
`F_("restoring") =4a^(2) rho gx ..(2)`
As force constants on two sides of equilibrium positions are not same, amplitude of oscillation on two sides different.
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