For `SHM` to take place force acting on the body should be proportional to `-x` or `F =- kx`. If `A` be the amplitude then enegry of oscillation is `1//2KA^(2)`.
If enegry of oscillation is `18J`, between what points does the block will oscillate?

Options

A. between `x =0` nad `x =4m`
B. between `x =-1m` and `x =5 m`
C. between `x =-2` and `x =6m`
D. between `x =1m` and `x =3m`

Answer

B

Explanation

`F =-4X, k = 4N//m, A =sqrt((2E)/(k)) = sqrt(2xx18)/(4) =3m` mean position is `x =2m`. Hence, the exterme points are `5m` and -1m`.