The distabce travelled in a time, t by a particle moving along `x`-axis according to an equation `x = A cos omegat` is given by `S = nA +S_(0)`, when time `t` can be written as `t =n((T)/(4)) +t_(0)` such that `t_(0) lt T//4` and distance travelled in that `t_(0)` is `S_(0)`.
The distance `S` is, when 'n' is odd number.

Options

A. `S =A [(n+1) -cos (omegat+(npi)/(2))]`
B. `S = A[(n+1)-cos (omegat-(npi)/(2))]`
C. `S = A[n +sin (omegat -(npi)/(2))]`
D. `S = A [(n+1)-sin (omegat-(npi)/(2))]`

Answer

C

Explanation

`S = nA +S_(0), S_(0) = x_(0) = A sin wt_(0)`