A point moves in the plane `y` according to the law `x = A sin omegat, y = B cos omegat`, where`A,B & omega` are positive constant.
The velocity of particle is given by

Options

A. `v = sqrt(A^(2) +B^(2)) omega`
B. `v = sqrt(A^(2)cos^(2) omegat +B^(2) sin^(2) omegat)omega`
C. `v = omega sqrt((A^(2)+B^(2))-(x^(2)+y^(2)))`
D. `v = omega sqrt((A+B)^(2)-(x+y)^(2))`

Answer

B

Explanation

`v_(x) = (dx)/(dt),v_(y) = (dy)/(dt) = v = sqrt(v_(x)^(2) +v_(y)^(2))`