Home
Class 11
PHYSICS
A body of mass 1//4 kg is in SHM and its...

A body of mass `1//4 kg` is in `SHM` and its displacement is given by the relation `x = 0.05 Sin(20t +(pi)/(2))m`. If is in seconds, the maximum force acting on the particle is

A

`5N`

B

`2.5N`

C

`10N`

D

`0.25N`

Text Solution

Verified by Experts

The correct Answer is:
A
`F = ma, a = omega^(2)A`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    NARAYNA|Exercise ENERGY OF A PARTICLE EXECUTING SHM|9 Videos

  • OSCILLATIONS

    NARAYNA|Exercise OSCILLATIONS DUE TO A SPRING|13 Videos

  • OSCILLATIONS

    NARAYNA|Exercise DISPLACEMENT|6 Videos

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise PASSAGE TYPE QUESTION|6 Videos

  • PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|10 Videos

Similar Questions

Explore conceptually related problems

A particle of mass 4 kg is executing S.H.M. Its displacement is given by the equation Y=8 cos[100t+pi//4] cm. Its maximum kinetic energy is

If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is

A body of mass 3 kg is under a constant force which causes a displacement s metre in it, given by the relation s=(1)/(3)t^(2) , where t is in seconds. Work done by the force in 2 seconds is

A body of mass 1 is executing simple harmonic motion. Its displacement y(cm) at t seconds is given by y = 6 sin (100t + pi//4) . Its maximum kinetic energy is

A body of mass 5 kg is moving in a straight line. The relation between its displacement and time t is given by x=(t^(3)-2t-10) metre. What is the force acting onit at the end of second?

The equation of displacement of a particle performing a S.H.M. is x=0.25 "sin" (200 t) metre. What is the maximum velocity of the particle ?