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Due to some force F(1) a body oscillates...

Due to some force `F_(1)` a body oscillates with period `4//5s` and due to other force `F_(2)` it oscillates with period `3//5s`. If both the forces acts simultaneously in same direction then new period is

A

`0.72 s`

B

`0.64s`

C

`0.48s`

D

`0.36s`

Text Solution

Verified by Experts

The correct Answer is:
C
`F alpha (1)/(T^(2))`
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