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The time period of a mass loaded spring ...

The time period of a mass loaded spring is 'T'. If `20%` of its turns are cut and removed and same mass is attached to the remaining spring then it oscillates with a period of

A

`(5T)/(4)`

B

`(sqrt(5)T)/(2)`

C

`(4T)/(5)`

D

`(2T)/(sqrt(5))`

Text Solution

Verified by Experts

The correct Answer is:
D
`T = 2pi sqrt((m)/(K)), K alpha (1)/(l)`
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