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Three block of masses m(1) = 10kg, m(2) ...

Three block of masses `m_(1) = 10kg, m_(2) =20 kg` and `m_(3) = 30kg` are on a smooth horizontal table ,connected to each other by light horizontal string. A horizontal placed force `F = 60N` is applied to `m_(3)`, towards right find
(a) tension`T_(1)` and `T_(2)` and
(b) tension`T_(2)` if all of a sudden the string between `m_(1)` and `m_(2)` snaps.

A

`10N,10N`

B

`30N,10N`

C

`10N,30N`

D

`30N,30N`

Text Solution

Verified by Experts

The correct Answer is:
C

`T_(3)-T_(2)=m_(3)a`,
`T_(2)-T_(1)=m_(2)a,T_(1)=m_(1)a,a=T_(3)/(m_(1)+m_(2)+m_(3))`
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