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A marble block of mass 2 kg lying on ice...

A marble block of mass 2 kg lying on ice when given a velocity of `6m//s` is stopped by friction in 10s. Then the coefficient of friction is

A

`0.02`

B

`0.03`

C

`0.06`

D

`0.01`

Text Solution

Verified by Experts

The correct Answer is:
C
`v=u+at,a=mu_(k)g`
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