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Three blocks of equal masses (each `3kg`) are suspended by weightless strings as shown. If applied force is `100N`,then `T_(1)` is equal to `(g=10m//s^(2))`

A

`130 N`

B

`190 N`

C

`100 N`

D

`160 N`

Text Solution

Verified by Experts

The correct Answer is:
A
`T_(1)=F+mg`
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