Accelertion of block m is (theta lt 45^(...

Accelertion of block `m` is `(theta lt 45^(@))`

`g sin theta`

`g cos theta`

`g (cos theta+sin theta)`

`g (cos theta-sin theta)`

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The correct Answer is:

`F_(R)=mg cos theta-mg sin theta`

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Acceleration of block m is (theta lt 45^(@))

In the figure shown, angle of repose is 45^(@) .Find force of friction, net force and acceleration of the block when (a) theta = 30^(@) (b) theta = 45^(@) (c) theta = 60^(@)

Consider the following statements : 1. If 45^(@) lt theta lt 60^(@) , then sec^(2) theta + cosec^(2) theta = alpha^(2) for some real number alpha gt 1 . 2. If 0^(@) lt theta lt 45^(@) , then (1 + cos theta)/(1- cos theta) = x^(2) for some real number x gt 2 . 3. If 0^(@) lt theta lt 45^(@) , then (cos theta)/(1- tan theta) + (sin theta)/(1 - cot theta) ge 2 . What is the number of true statements ?

A block of mass m is placed on a rough plane inclined at an angle theta with the horizontal. The coefficient of friction between the block and inclined plane is mu . If theta lt tan^(-1) (mu) , then net contact force exerted by the plane on the block is :

In the previous problem ,find the magnitude of change in velocity if (a) 90^(@) lt theta lt 180^(@) , (b) 180^(@) lt theta lt 270^(@) and (c ) 270^(@) lt theta lt 360^(@) .

What is the value of theta, 0^(@) lt theta lt 90^(@), " if " cos theta + sin theta = sqrt(2) ?

A block of mass m is placed on a wedge of mass M. Coefficient between then is mu lt cot theta . The wedge is given an acceleration to its left. Find the maximum acceleration at which block apears stationary relative to wedge.

If sin theta = sqrt(3) cos theta, 0 lt theta lt 90^(@) , then theta is equal to .

NARAYNA-CIRCULAR MOTION-LEVEL II(H.W)

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