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A person of mass 72kg sitting on ice pus...

A person of mass `72kg` sitting on ice pushes a block of mass of `30kg` on ice horizontally with a speed of `12ms^(-1)`.The coefficient of friction between the man and ice and between block and ice is `0.02`.If `g=10ms^(-1)`,the distance between man and the block, when they come to rest is

A

`360m`

B

`10m`

C

`350m`

D

`422.5m`

Text Solution

Verified by Experts

The correct Answer is:
D
`S_(1)=v^(2)/(2mug)`,Form L.C.M find `v^(1)`
`S_(2)=v^(1^(2))/(2mug), S=S_(1)+S_(2)`
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