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A box is placed on the floor of a truck ...

A box is placed on the floor of a truck moving with an acceleration of `7 ms^(2)`.If the coeffecient of kenetic friction between the box and surface of the truck is `0.5`,find the acceleration of the box relative to the truck

A

`1.7 ms^(-2)`

B

`2.1 ms^(-2)`

C

`3.5 ms^(-2)`

D

`4.5 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`f_(k)=mu_(k)N,N=mg,a^(1)=mu_(k)g,a_(rel)=a-a^(1)`
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Knowledge Check

  • A box mass m kg is placed on the rear side of an open truck acceleration at 4ms^(-2) . The coefficient of friction between the box ant the surface below it is 0.4 . The net acceleration of the box with respect to the truck is zero. The value of m is.

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