A ball of mass `m_(1)`, collides elastically and head on with ball of mass `m_(2)` at rest. Then

Options

A. The transfer of kinetic energy to the second ball is maximum when `m_(1) = m_(2)`
B. The change of momentum of first ball is maximum, when `m_(1) lt lt m_(2)`.
C. The velocity of the second ball is maximum, when `m_(1) gt gt m_(2)`.
D. None of these

Answer

A, B, C

Explanation

Velocity of first ball after the collision is
`v_(1) = ((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1)+(2m_(2)u_(2))/(m_(1)+m_(2))`
If `m_(1) = m_(2)` , `v_(1) = 0`, `v_(2) = u_(1)`
In this case whole of the `K.E.` is transferred to the second ball after the collision.
If `m_(1) lt lt m_(2) , v_(1) = u_(1)` and `v_(2) = 2u_(1)`