Two particles of mases `m` and `m'` moving on parallel straight lines are at the distance `'a'` apart with velocities `v` and `v'(v gt v')`. The particles are connected by a string of length `( gt a)` which was loose in the beginning. Calculate the impluse of tension of the string when it becomes taut.

Answer

`(m m'(v-v')sqrt(l^(2)-a^(2)))/((m+m')l)`

Explanation

Just before string becomes taut

Just after string becomes taut.
`T Delta t = m(V cos theta-V'') , T Delta t = m'(V''-V' cos theta)`
`rArr v'' = ((m v+m'v') cos theta)/((m+m'))`
`T Delta t = J = (m m'(V-V')sqrt(l^(2)-a^(2)))/((m+m')l)`