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A ball of 4 kg mass moving with a speed ...

A ball of `4 kg` mass moving with a speed of `3ms^(-1)` has a head on elastic collision with a `6 kg` mass initially at rest. The speeds of both the bodies after collision are respectively

A

`0.6 ms^(-1), 2.4 ms^(-1)`

B

`-0.6 ms^(-1), -2.4 ms^(-1)`

C

`-0.6 ms^(-1), 2.4 ms^(-1)`

D

`-0.6 ms^(-1), -2.4 ms^(-1)`

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The correct Answer is:
To solve the problem of an elastic collision between a 4 kg ball moving at 3 m/s and a 6 kg ball initially at rest, we will use the principles of conservation of momentum and the properties of elastic collisions. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Mass of ball 1 (m1) = 4 kg - Initial velocity of ball 1 (u1) = 3 m/s - Mass of ball 2 (m2) = 6 kg - Initial velocity of ball 2 (u2) = 0 m/s (since it is at rest) 2. **Conservation of Momentum:** The total momentum before the collision is equal to the total momentum after the collision. \[ m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2 \] Substituting the known values: \[ 4 \times 3 + 6 \times 0 = 4 v_1 + 6 v_2 \] This simplifies to: \[ 12 = 4 v_1 + 6 v_2 \quad \text{(Equation 1)} \] 3. **Elastic Collision Condition:** For an elastic collision, the relative velocity of separation is equal to the relative velocity of approach. \[ v_2 - v_1 = u_1 - u_2 \] Substituting the known values: \[ v_2 - v_1 = 3 - 0 \] This simplifies to: \[ v_2 - v_1 = 3 \quad \text{(Equation 2)} \] 4. **Solve Equations Simultaneously:** From Equation 2, we can express \(v_2\) in terms of \(v_1\): \[ v_2 = v_1 + 3 \] Now substitute \(v_2\) in Equation 1: \[ 12 = 4 v_1 + 6(v_1 + 3) \] Expanding this gives: \[ 12 = 4 v_1 + 6 v_1 + 18 \] Combining like terms: \[ 12 = 10 v_1 + 18 \] Rearranging gives: \[ 10 v_1 = 12 - 18 \] \[ 10 v_1 = -6 \] \[ v_1 = -0.6 \, \text{m/s} \] 5. **Find \(v_2\):** Now substitute \(v_1\) back into the equation for \(v_2\): \[ v_2 = -0.6 + 3 = 2.4 \, \text{m/s} \] ### Final Answer: - The speed of the 4 kg ball after the collision (v1) is **-0.6 m/s** (indicating it moves in the opposite direction). - The speed of the 6 kg ball after the collision (v2) is **2.4 m/s**.

To solve the problem of an elastic collision between a 4 kg ball moving at 3 m/s and a 6 kg ball initially at rest, we will use the principles of conservation of momentum and the properties of elastic collisions. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Mass of ball 1 (m1) = 4 kg - Initial velocity of ball 1 (u1) = 3 m/s - Mass of ball 2 (m2) = 6 kg ...
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