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A spring of force constant 800 Nm^(-1) i...

A spring of force constant `800 Nm^(-1)` is stretched initially by `5 cm`. The work done in stretching from `5 cm` to `15 cm` is

A

`12.50 N-m`

B

`18.75 N-m`

C

`25.00 N-m`

D

`6.25 N-m`

Text Solution

Verified by Experts

The correct Answer is:
C
`W = (1)/(2)K(x_(2)^(2)-x_(1)^(2))`
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