A ball of mass m is thrown in air with speed `v_(1)` from a height `h_(1)` and it is at a height `h_(2)(gth_(1))` when its speed becomes `v_(2)` . Find the work done on the ball the air resistance.

Options

A. `m g(h_(2)-h_(1))+(1)/(2)m(v_(2)^(2)-v_(1)^(2))`
B. `m g(h_(2)-h_(1))`
C. `(1)/(2)m(v_(2)^(2)-v_(1)^(2))`
D. `m g (h_(2)-h_(1))-(1)/(2)(v_(2)^(2)-v_(1)^(2))`

Answer

A

Explanation

`W_("mg")+W_("air") = Delta K.E`.